[Spread-users] Fwd: Spread 4.1 <members list>

[Vinoth]

>
> > I know that using membership messages we can get the list of members
> > available for that group.
> > But my requirement is, I need to periodically check the spread group and
> get
> > the list of active members. Is there any other way to get the list of
> > members by giving the group name??
>
> there isn't, as far as I know.
> Clients are supposed to implement this functionality on their own,
> using join/leave notifications


Fine Alexey
So apart from these join/leave notifications we can't find a solution for
this am i right?.
or Is there any other implementation that we can do it on our own???


>
>
> > Am trying hard to find a direct solution for this,
> > it will be great if you could help me in this regard.
> >
> > cheers,
> > Vinoth
> > On Fri, Aug 28, 2009 at 9:39 PM, Dave Koberstein <davek at davek.org>
> wrote:
> >>
> >> Hi Vinoth,
> >>
> >> When you join you get a membership message that lists the other group
> >> members.  Just to get a quick sense of it, try using the spuser
> application
> >> and join the group.  It will print out the members when it joins.
> >>
> >> It's also an example of getting the membership info using the C API.
> >>
> >> After joined, you get membership messages as others join or leave the
> >> group.
> >>
> >> Dave k
> >>
> >> On 8/28/2009 4:08 AM, Vinoth wrote:
> >>
> >> Hi All,
> >>
> >> Greetings!. I am currently using spread 4.1.0 in my application. I
> >> connected to Spread and joined into a group. I want to list all members
> for
> >> that group.
> >> Is it possible? If not, then can any one please suggest the alternative
> >> for this.
> >>
> >> I just want to pro actively check the spread group for its active
> members.
> >>
> >> --Cheers,
> >> Vino
> >>
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> >> Spread-users at lists.spread.org
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> >>
> >
> > _______________________________________________
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> > Spread-users at lists.spread.org
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> >
> >
>
>
>
> --
> Alexey Zakhlestin
> http://www.milkfarmsoft.com/
> Sent from St Petersburg, Russian Federation
>



-- 
Cheers,
Vinoth
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