[Spread-users] Re: Please help me understand

apocalypznow apocalypznow at gmail.com
Wed Feb 9 16:08:21 EST 2005


Thanks Mike for drawing the diagram.  Your diagram seems to reflect what 
I said.... but because the diagram is distorted in my news reader, I am 
not 100% sure of it.  Here is another description, just for clarity:

24.83.9.162 is a public ip, has a router, from which 192.168.0.100 and 
192.168.0.101 are behind that.  64.80.10.152 is another public ip (on 
another network), has a router, from which 192.168.0.102 and 
192.168.0.103 are behind.

The answer (to Q #2) that John Schultz gave implies to me that it can be 
done, but you've said otherwise.  Why is that?



Mike Perik wrote:
> I think what apocalypznow is saying is that 
> 24.83.9.162 and 64.80.10.152 are the public ip addresses that two routes have and behind one router are two machines 192.168.0.100 and 192.168.0.101 and behind another router are two machines 192.168.0.102 and 192.168.0.103
> 
>         ____________                                    ____________
>        |   24.83.9.162   |--------------------------|   64.80.10.152 |
>        |____________|                                  |____________|
>           /                     \                                           /                      \ 
> 192.168.0.100  192.158.0.101   192.168.0.102    192.168.0.103
> 
> 
> I'm not sure what the spread.conf would look like in this situation.
> I think the answer that John gave to question # 2 implies that no you can't do this.
> 
> Correct?
> 
> 
> Mike 
> 
> On Wednesday 09 February 2005 01:56 pm, John Schultz wrote:
> 
>>apocalypznow wrote:
>>
>>>Hi I'm a noob... so please bear with me.
>>>
>>>I am trying to set up 4 machines on 2 networks, which would all join the
>>>same group "chat01" and hopefully be able to message each other using
>>>multicast() with either RELIABLE_MESS or FIFO_MESS.
>>>Two machines are at 24.83.9.162, and their ips are 192.168.0.100 and
>>>192.168.0.101.  Two other machines are at 64.80.10.152 and their ips are
>>>at 192.168.0.102 and 192.168.0.103.  Port 4803 is open on each of the
>>>two routers.  Networks 24.83.9.162 and 64.80.10.152 are only connected
>>>on the internet.
>>>
>>>I've tried various configurations in my spread.conf file and I can't get
>>>all 4 machines to see any messages sent to the same group "chat01".
>>>
>>>Questions:
>>>1) How should my spread.conf be set up - specifically the segments and
>>>anything else?
>>
>>You should probably have two segments corresponding to the two separate
>>networks -- assuming that by "networks" you mean that machines within




>>these "networks" can 1 hop broadcast or multicast to each another.
>>
>>
>>>2) Where do I run the daemons?
>>
>>You should run the daemons on machines whose IP addresses are accessible
>>  (i.e. - routable) by all other daemons in the config file.  So the
>>daemons should be run on machines in those networks that can reach the
>>daemons on the other network.
>>
>>
>>>3) How many daemons should I run?
>>
>>This is up to you.  But generally you should run at least one daemon per
>>network that will have clients and usually even run 1 daemon on each
>>machine that will have clients.  You run more daemons both for network
>>efficiency and for fault tolerance.
>>
>>
>>>4) To which daemon should each machine connect to?
>>
>>Each machine should connect to the closest daemon that it can.  Usually,
>>   this is often a connection to a daemon on the same local machine.
>>However, since it seems your client machines will be on private networks
>>that would not be routable by all daemons, you will probably need to
>>remotely connect to the closest daemon with a public IP.





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